Question

simplify the following numbers by rationalizing the denominator: 6 upon root 2 + root 3 please its urgent​

Answer 1

$\frac{6}{ \sqrt{2} + \sqrt{3} } \\ = \frac{6}{ \sqrt{2} + \sqrt{3} } \times 1 \\ = \frac{6}{ \sqrt{2} + \sqrt{3} } \times \frac{ \sqrt{2} - \sqrt{3} }{ \sqrt{2} - \sqrt{3} } \\ = \frac{6 \times ( \sqrt{2} - \sqrt{3} ) }{ { (\sqrt{2}) }^{2} - {( \sqrt{3}) }^{2} } \\ = \frac{6 \times ( - 1) \times ( \sqrt{3} - \sqrt{2)} }{2 - 3} \\ = \frac{6 \times ( - 1) \times ( \sqrt{3} - \sqrt{2} ) }{( - 1)} \\ = 6 \times ( \sqrt{3} - \sqrt{2)}$