Math, asked by sushantkrsushant186, 10 months ago

simplify the following . question no. i to iv all​

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Answered by Anonymous
1

Answer:

(i) taking common xy

then , xy( -3xy² × 2 yx² × 5 ) = 0

-6xy² ×5

-30xy²

Answered by archnakri2007
4

Step-by-step explanation:

3.

(i) -3xy^3 × 2yx^3 × 5xy

= ( -3 × 2 × 5 ) × x × x × x × x × x × y × y × y × y × y

= -30x^5y^5

(ii) 2/5x^2y × (-1/2z^2) × (-15y^2xz)

= ( 2/5 × 1/2 × 15 ) × x × x × x × y × y × y × z × z × z

= 3x^3y^3z^3

(iii) 1/8a^2b^4 × 1/4ab × a^4b^2 × 5

= ( 1/8 × 1/4 × 5 ) × a × a × a × a × a × a × a × b × b × b × b × b × b × b

= 5/32a^7b^7

(iv) -5p^2q × 8/15pqr^2 × (-1/4r) × (-2/3pq^2)

= {(-5 × 8/15 × (-1/4) × (-2/3)} × p × p × p × p × q × q × q × q × r × r × r

= - 4/9p^4q^4r^3

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