Question

Simplify the given question .....with steps ...
$(6 \times 8 {}^{n + 1} + 16 \times 2 {}^{3n - 2)} ) \div 10 \times 2 {}^{(3n + 1)} - 7 \times 8 {}^{n}$

Answer 1

Hi ,

It is given that ,

6 × 2^3n+3 + 16 × 2^3n-2

= 6 × ( 2^3n × 2³ ) + 16 × ( 2^3n/2² )

[ Since 1 ) a^m+n = a^m × a^n

2) a^m-n = a^m/a^n ]

= 6 × 2^3n × 8 + 16 × (2^3n)/4

= 2^3n[ 48 + 4 ]

= 2^3n × 52

= 52 × 2^3n

I hope this helps you.

: )