Question

simplify the question​

Answer 1

Step-by-step explanation:

$9x^{2} - 16y^{2}$ = (3x-4y)(3x+4y)

$2x^{2} + 3x - 20$ = (2x-5)(x+4)

$\frac{x+4}{3x+4y} * \frac{9x^{2} - 16y^{2} }{2x^{2}+3x-20 }$ = $\frac{3x-4y}{2x-5}$ -----Answer