simplify this question
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Identity: x³+y³+z³=3xyz when x+y+z=0
Using the above identity,
=3(a²-b²)(b²-c²)(c²-a²)/3(a-b)(b-c)(c-a)
=(a+b)(b+c)(c+a)
Using the above identity,
=3(a²-b²)(b²-c²)(c²-a²)/3(a-b)(b-c)(c-a)
=(a+b)(b+c)(c+a)
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I think it is helpful for you
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SINGHisKING11:
thanks bhai
x³+y³+z³=3xyz only when x+y+z=0
you should mention this
ok
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