Question

Simplify this question​

Answer 1

Answer:

0 ANSWER

Step-by-step explanation:

$\frac{1}{i} + \frac{1}{ {i}^{2} } + \frac{1}{ {i}^{3} } + \frac{1}{ {i}^{4} } = - i - 1 + i + 1 \\ \\ = 0.$

Answer 2

Answer:

0

Step-by-step explanation:

$\frac{ 1 }{ i } + \frac{ 1 }{ i ^ { 2 } } + \frac{ 1 }{ i ^ { 3 } } + \frac{ 1 }{ i ^ { 4 } } \\ = \frac{i}{-1}+\frac{1}{i^{2}}+\frac{1}{i^{3}}+\frac{1}{i^{4}} \\ = -i+\frac{1}{i^{2}}+\frac{1}{i^{3}}+\frac{1}{i^{4}} \\ = -i+\frac{1}{-1}+\frac{1}{i^{3}}+\frac{1}{i^{4}} \\ = -i-1+\frac{1}{i^{3}}+\frac{1}{i^{4}} \\ = -i-1+\frac{1}{-i}+\frac{1}{i^{4}} \\ = -i-1+\frac{i}{1}+\frac{1}{i^{4}} \\ = -i-1+i+\frac{1}{i^{4}} \\ = \frac{1}{i^{4}}-1 \\ = \frac{1}{1}-1 \\ = 1-1 = 0$

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