Question

Simplify this sum with steps ... NO SPAM

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

$\displaystyle\longrightarrow\sf {\dfrac {\sqrt{32}+\sqrt {48}}{\sqrt8+\sqrt{12}}=\dfrac {\sqrt{4\times8}+\sqrt {4\times 12}}{\sqrt8+\sqrt{12}}}$

$\quad$

$\displaystyle\longrightarrow\sf {\dfrac {\sqrt{32}+\sqrt {48}}{\sqrt8+\sqrt{12}}=\dfrac {\sqrt{4}\times\sqrt{8}+\sqrt {4}\times \sqrt{12}}{\sqrt8+\sqrt{12}}}$

$\quad$

$\displaystyle\longrightarrow\sf {\dfrac {\sqrt{32}+\sqrt {48}}{\sqrt8+\sqrt{12}}=\dfrac {2\sqrt{8}+2\sqrt {12}}{\sqrt8+\sqrt{12}}}$

$\quad$

$\displaystyle\longrightarrow\sf {\dfrac {\sqrt{32}+\sqrt {48}}{\sqrt8+\sqrt{12}}=\dfrac {2(\sqrt{8}+\sqrt {12})}{\sqrt8+\sqrt{12}}}$

$\quad$

$\displaystyle\longrightarrow\sf {\underline {\underline {\dfrac {\sqrt{32}+\sqrt {48}}{\sqrt8+\sqrt{12}}=2}}}$