Question

simplify using bodmas rule​

Answer 1

$\huge \mathbb\fcolorbox{black}{paleturquoise}{Answer}$

Step-by-step explanation:

$10 \frac{1}{2} - (8 \frac{1}{2} + (6 - (7 - 2))) \\ \frac{21}{2} - ( \frac{17}{2} + (6 - 5)) \\ \frac{21}{2} - ( \frac{17}{2} + 1) \\ \frac{21}{2} - ( \frac{17 + 2}{2} ) \\ \frac{21}{2} - \frac{19}{2} \\ \\ \frac{21 - 19}{2} \\ = \frac{2}{2} = 1$

Answer 2

Given that

$10 \frac{1}{2} - (8 \frac{1}{2} +( 6 - (7 - bar(6 - 4)))$

To simplify it

Solution

As given equation has to solve by using VBODMAS rule

In this rule

Operation perform sequentially as Viniculum,B as bracket,then Of ,Division,Multiplication,Addition and subtraction.

In this we will first solve bar we get

$10 \frac{1}{2} - (8 \frac{1}{2} +( 6 - (7 - 2)))$

now by subtraction we get

$10 \frac{1}{2} - (8 \frac{1}{2} + (6 - 5))$

as again subtraction we get

$10 \frac{1}{2} - (8 \frac{1}{2} + 1)$

now we will convert mixed fraction into fraction as

$\frac{10 \times 2 + 1}{2} - ( \frac{16 + 1}{2} + 1)$

now by multiplication and add we get

$\frac{21}{2} -( \frac{17}{2} + 1)$

by cross multiplication in bracket we get

$\frac{21}{2} - \frac{19}{2}$

as the base is same hence

$\frac{21 - 19}{2}$

by subtraction

$\frac{2}{2}$

by division

$1$

Hence Answer is 1.