Math, asked by rinaasingh3i, 2 months ago


Simplify
(vi) 12 (6+2)
Add the following
(1) 7314 348, 7314, 121
(11) 398, -2 1734. -1034
(1) 300 + (-78) + (-22)
(iv) (-365) + (-35) + 1400
(V) 5+ (425) + ( -275 ) + 600

9. Simplify the following:
(a) 132 - (143) + 96 - (-24)
(b) 150 - (-148) + 2
(C) -178 (-522) + (-410)
(d) 12 + (-36) - (-42) + 23
10. The sum of 2 integers is 418. If one of them is -246. Find the other.
11. The sum of two integers is -72. If one of them is -43. Find the other.
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Answers

Answered by alkabenjayeshpatel
1

Step-by-step explanation:

(vi) 12 ( 6 + 2 )

72 + 24

96

Add The following

(i) 7314 + 348 + 7314 + 121

7662 + 7435

15097

(ii)398 + ( - 2 ) + 1734 + ( - 1034 )

398 - 2 + 1734 - 1034

396 + 700

1096

(iii) 300 + ( - 78 ) + ( - 22 )

300 - 78 - 22

200

(iv) ( - 365 ) + ( - 35 ) + 1400

- 365 - 35 + 1400

1000

(v) 5 + 425 + ( - 275 ) + 600

430 - 275 + 600

755

Simplify the following :

(a) 132 - 143 + 96 - ( - 24 )

- 11 + 120

109

(b) 150 - ( - 148 ) + 2

150 + 148 + 2

300

(c) - 178 - 522 + ( - 410 )

- 700 - 410

- 1110

(d) 12 + ( - 36 ) - ( - 42 ) + 23

12 - 36 + 42 + 23

- 24 + 65

41

10. Let the other integer be x

x + ( - 246 ) = 418

x = 418 + 246

x = 664

11. Let the other integer be x

x + ( - 43 ) = - 72

x = - 72 + 43

x = - 23

Hope it helps!!

Answered by kd1030601
38

Answer:

I hope it will help you

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