Question

Simplify √x÷√2+√2 by rationalizing the denominator

Answer 1

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↪ Here is your answer :

$\sqrt{x} \div \sqrt{2} + \sqrt{2 } \\ \sqrt{x} \div \sqrt{2} + \sqrt{2} \times \sqrt{2} - \sqrt{2} \div \sqrt{2} - \sqrt{2} \\ \sqrt{x} ( \sqrt{2} - \sqrt{2} ) \div ( \sqrt{2} + \sqrt{2} )( \sqrt{2} - \sqrt{2} ) \\ now \: the \: denominator \: becomes \: an \: identity \: which \: is \: (a + b) \: (a - b) = (a ^{2} - b ^{2} ) \\ so \: (\sqrt{2} ^{2} ) - ( \sqrt{2} ^{2} ) = 2 - 2 = 0 \\ so \: \sqrt{x} ( \sqrt{2} - \sqrt{2} ) \div 0$

${Here\:the\:denominator \:is\:0\:which \:is\:a\:rational\:number}$

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