simplify x^a-b/x^c-b * x^c-a
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1 is the answer of this question ..this is the method to solve this
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truemathsacademy:
thank yo
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Hi ,
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By Exponential Laws:
1) a^m/a^n = a^m-n
2 ) a^m × a^n = a^m+n
3 ) x^0 = 1
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Here,
[ x^a-b/x^c-b ] × x^c-a
= x^(a-b)-(c-b) × x^c-a
= x^(a-b-c+b) × x^c-a
= x^a-c × x^c-a
= x^a-c+c-a
= x^0
= 1
I hope this helps you.
: )
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