Simplify :- (x+y)- 1/2 (2+x-2y) .
Answers
Answered by
22
Hi ,
x + y - 1/2 (2 + x - 2y )
= x + y - ( 1/2 × 2) - (1/2 × x )+ (1/2 × 2y)
= x + y - 1 - x/2 + y
= ( x - x/2 ) + ( y + y ) - 1
= x/2 + 2y - 1
Or
( x + y ) - 1/2 ( 2 + x - 2y )
= [ 2( x + y ) - ( 2 + x - 2y ) ]/2
= ( 2x + 2y - 2 -x + 2y )/2
= ( x + 4y - 2 ) /2
= x/2 + 4y/2 - 2/2
= x/2 + 2y - 1
I hope this helps you.
:)
x + y - 1/2 (2 + x - 2y )
= x + y - ( 1/2 × 2) - (1/2 × x )+ (1/2 × 2y)
= x + y - 1 - x/2 + y
= ( x - x/2 ) + ( y + y ) - 1
= x/2 + 2y - 1
Or
( x + y ) - 1/2 ( 2 + x - 2y )
= [ 2( x + y ) - ( 2 + x - 2y ) ]/2
= ( 2x + 2y - 2 -x + 2y )/2
= ( x + 4y - 2 ) /2
= x/2 + 4y/2 - 2/2
= x/2 + 2y - 1
I hope this helps you.
:)
Answered by
8
Hello !
x + y - 1/2 (2 + x - 2y )
Opening the brackets:-
x + y - (1/2*2) - (1/2 *x)+ (1/2 *2y)
x + y - 1 - x/2 + y
grouping like terms,
( x - x/2 ) + ( y + y ) - 1
(2x - x) /2 + 2y - 1
x/2 + 2y - 1 ----> Required answer
x + y - 1/2 (2 + x - 2y )
Opening the brackets:-
x + y - (1/2*2) - (1/2 *x)+ (1/2 *2y)
x + y - 1 - x/2 + y
grouping like terms,
( x - x/2 ) + ( y + y ) - 1
(2x - x) /2 + 2y - 1
x/2 + 2y - 1 ----> Required answer
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