Question

simplify (x+y+z)^2-(x-y+z)^2​

Answer 1

Answer:

(x+y+z)²-(x-y+z)²

= x²+y²+z² - x²+y²-z²

=2y²

Here x²- x² and z²-z² gives 0

So answer is 2y²

Sorry if its not right

Answer 2

Step-by-step explanation:

as we compare to a^2-b^2=(a+b)(a-b)

(x+y+z)^2-(x-y+z)^2=(x+y+z+x-y+z)(x+y+z-x+y-z)

=(2x+2z)(2y)

=4(xy+yz)

hope it's helpful