Simplify (xy + yz)2 – 2x2
y2
z. Find the value when x = -1, y = 1 and z = 2.
Answers
Answered by
3
HEY THERE!!!
Question-
(xy+yz)² -2x²+y²
Method of Solution;-
Substitute the given value in Equation;
(xy+yz)² -2x²+y²
[(-1×1) + (1×2)]² - 2(-1)² + (1)²
[ -1+2]² -2(1) +1
=>[1]² -2+1
==>1-2+1
=>1+1 -2
=> 2-2
=> 0
Hence, Value of this Equation is 0
Question-
(xy+yz)² -2x²+y²
Method of Solution;-
Substitute the given value in Equation;
(xy+yz)² -2x²+y²
[(-1×1) + (1×2)]² - 2(-1)² + (1)²
[ -1+2]² -2(1) +1
=>[1]² -2+1
==>1-2+1
=>1+1 -2
=> 2-2
=> 0
Hence, Value of this Equation is 0
jaykrishvara7:
sorry my question was wrong i has send new right question
it's okay
can i send the new equation
(xy+yz)^2 - 2x^2y^2z
ans = 1
Answered by
0
Answer:
no problem at all of this poor little
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