simplifya(b-c)-b(c-a)-c(a-b)
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Answered by
1
Answer:
2a(b-c)
Step-by-step explanation:
a(b-c) -b(c-a) -c(a-b)
=> ab - ac - bc +ab - ac + bc
=> ab + ab - ac - ac - bc + bc
=> 2ab - 2ac
=> 2a(b-c)
Answered by
0
Answer:
a-(b-c) -b(c-a) -c(a-b)
= a-b+c-b + c -a - c + a - b
= a+a-a-b-b-b +c+c-c
= 2a-a-b-b -b+c+c-c
= a-2b-b+c+c-c
= a-3b+c+c-c
= a-3b+2c-c
=a-3b+c
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