Math, asked by mohommadbin096, 3 days ago

simply 2 log 3+3log2+log5-log12

Answers

Answered by devilrishu5030

1

Answer:

2log3+3log2+log5−log12=log3

2

+log2

3

+log5−log12

=log9+log8+log5−log12

=log9×8×5−log12

=log360−log12

=log

12

360

=log30

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