Question

simply tan 3x + tan 2x​

Answer 1

Answer:

Given tan2x−tan3x

→tan2x−tan3x=tan(−x)(1+tan2xtan3x)=0

So, either tanx=0⇒x=nπ∀n∈z  

OR

→tan2xtan3x=−1

→sin2xsin3x+cos2xcos3x=0

→cosx=0

→x=(2n+1)2π∀n∈z 

Step-by-step explanation:

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