simply the following (3a+b)³+(3a_b)³
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Answered by
1
Answer:
9a³-b³-21a²b+9ab²+3a+b
Step-by-step explanation:
(3a+b)+(3a-b)×(3a-b)×(3a-b)
=(3a+b)+(3a-b)²×(3a-b)
=(3a+b)+[(3a)²-2(3a)(b)+(-b)²]×(3a-b)
=(3a+b)+(3a²-6ab+b²)×(3a-b)
=(3a+b)+3a(3a²-6ab+b²)-b(3a²-6ab+b²)
=(3a+b)+9a³-18a²b+3ab²-3a²b+6ab²-b³
=3a+b+9a³-18a²b+3ab²-3a²b+6ab²-b³
=9a³-b³-21a²b+9ab²+3a+b
Answered by
0
Answer:
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