Math, asked by srustigantayat82, 2 months ago

simply the following using identities:
(s²t+ tq²)²-(2stq)²

Answers

Answered by utkarskumar12

1

Answer:

(s2t+tq2+2stq)(s2t+tq2-2stq)

t[(s2+q2+2sq)(s2+q2-2sq)]

t[(s+q)2(s-q)2]

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