Question

simply this question ​

Answer 1

Step-by-step explanation:

18x^2y^2(3z-12)/36xy(z-6)

=3xy(z-4)/2xy(z-6)

Answer 2

$\frac{18 {x}^{2} {y}^{2}(3z - 12) }{36xy(z - 6)}$

$= \frac{ {x}^{2} {y}^{2} (3z - 12) }{2xy(z - 6)}$

$= \frac{xy \times3 (z - 4)}{2(z - 6)}$

$= \frac{3xy(z - 4)}{z - 6}$