Question

simplyfy 4√18/√12-8√75/√32+9√2/√3​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

The equation simplifies to 0

Given,

 $\frac{ 4\sqrt18}{\sqrt12} -\frac{8\sqrt75}{\sqrt32}+\frac{9\sqrt2}{\sqrt3}$

 $\frac{12\sqrt2}{2\sqrt3} - \frac{40\sqrt3}{4\sqrt2}+\frac{9\sqrt2}{\sqrt3}$

  $\frac{6\sqrt2}{\sqrt3} - \frac{10\sqrt3}{\sqrt2}+\frac{9\sqrt2}{\sqrt3}$           -(a)

Consider the term $\frac{6\sqrt2}{\sqrt3}$

By rationalizing the denominator we get,

$\frac{6\sqrt2}{\sqrt3}$  ×  $\frac{\sqrt3}{\sqrt3}$  =  $\frac{6\sqrt2\sqrt3}{3} = 2\sqrt6$           -(1)

Similarly consider the term $\frac{10\sqrt3}{\sqrt2}$

By rationalizing the denominator we get,

$\frac{10\sqrt3}{\sqrt2}$  ×  $\frac{\sqrt2}{\sqrt2}$  =  $\frac{10\sqrt3\sqrt2}{2} = 5\sqrt6$        -(2)

Similarly consider the term $\frac{9\sqrt2}{\sqrt3}$

By rationalizing the denominator we get,

$\frac{9\sqrt2}{\sqrt3}$  ×  $\frac{\sqrt3}{\sqrt3}$  =  $\frac{9\sqrt2\sqrt3}{3} = 3\sqrt6$           -(3)

Substituting equations (1) , (2) and (3) in equation (a), we get,

⇒  $2\sqrt6-5\sqrt6+3\sqrt6$

⇒  $\sqrt6 ( 2-5+3)$

⇒  $\sqrt6(0)$

⇒  0

Solution = 0

https://brainly.in/question/52554466

https://brainly.in/question/19211255

#SPJ2