Question

Simplyfy
log3 (4). log4 (81)​

Answer 1

Answer:

We have to evaluate in two parts:

First (log base 3 81)

We know that 81 = 3^4, So

Log base 3 3^4

We know that Log base A of A^b = b*Log base A of A

So

Log base 3 3^4 = 4*Log base 3 of 3

4*Log base 3 of 3 = 4*1

4*Log base 3 of 3 = 4

Then (log base 3 81) = 4

Now, log base 4 (log base 3 81) = log base 4 (4)

Using the main property of Logarithms: Log base A of A = 1

log base 4 of (4) = 1

The answer is: log base 4 (log base 3 81) = 1