Question

Simplyfy using the laws of exponents 3^3*64*81/18*4^2*3^5

Answer 1

Hey friend,
Here is the answer you were looking for:
$\frac{ {3}^{3} \times 64 \times 81 }{18 \times {4}^{2} \times {3}^{5} } \\ \\ = \frac{ {3}^{3} \times {2}^{6} \times {9}^{2} }{ 9 \times 2 \times {2}^{4} \times {3}^{5} } \\ \\ using \: the \: identity \\ \frac{ {a}^{m} }{ {a}^{n} } = {a}^{m - n} \\ \\ = {3}^{3 - 5} \times {2}^{6 - 5} \times {9}^{2 - 1} \\ \\ = {3}^{ - 2} \times 2 \times 9 \\ \\ = \frac{1}{ {3}^{2} } \times 2 \times 9 \\ \\ = \frac{1}{9} \times 2 \times 9 \\ \\ = 2$

Hope this helps!!!

@Mahak24

Thanks...
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