Math, asked by vinayakkerolkar, 9 months ago

simultaneous equations
3a+5b=26;a+5b=13​

Answers

Answered by Arshi1824
0

Answer:

(a,b) : (10,1.6)

Step-by-step explanation:

3a+5b=26____(1)

a+5b=13_____(2)

Subtracting eqn.(1) and eqn.(2)

3a+5b=26___(1)

a+5b=13____(2)

______________

4a. =39

a=39÷4

a=10

substituting value of a in equation (2)

a+5b=13

10+5b=13

5b=13-10

5b=3

b=3÷5

b=1.6

Answered by ltsmeAliya
0

Question:

Solve the Following Simultaneous Equation.

3a + 5b = 26;

a + 5b = 13

Step-by-step explanation:

3a + 5b = 26    ___(l)

a + 5b = 13    ___(ll)

Subtracting (ll) from (l)

2a = 13

a = 13/2

Putting the value of a = 13/2 in (ll)

a + 5b = 13

⇒ 13/2 + 5b = 13 - 13/2

⇒ 5b = 13/2

⇒ b = 13/10 = 1.3

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