Question

sin 0 =3/5 find cos 0 and tan 0 by trigonometric identity ​

Answer 1

Answer:

Using identity:

$sin^2A+cos^2A=1$

$(\frac{3}{5} )^2+cos^2A=1$

$cos^2A=1-(\frac{3}{5} )^2$

$cos^2A=1-\frac{9}{25}$

$cos^2A=\frac{25-9}{25}$

$cos^2A=\frac{16}{25}$

$cosA=\sqrt{\frac{16}{25} }$

$cosA=\frac{4}{5}$

Using identity:

$tanA=\frac{sinA}{cosA}$

$tanA=\frac{\frac{3}{5} }{\frac{4}{5} }$

$tanA=\frac{3}{5} * \frac{5}{4}$

$tanA=\frac{3}{4}$