Math, asked by abhishekdeori, 2 months ago

sin¢/1+cos¢=1-cos¢/sin¢

Answers

Answered by dikshatagala

0

Step-by-step explanation:

this is the solution for ur question....

Attachments:

Answered by sivakamivs

0

Answer:

LHS=sin¢/1+ cos¢

sin¢ × 1-cos¢

1 + cos¢. × 1 -cos¢

sin¢[1-cos¢]

1- cos²¢

sin¢[1- cos¢]

sin²¢

1- cos¢ = RHS

sin¢

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