(Sin¢/1+cos¢) +(1+cos¢/sin¢) is equal to *
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Answer:
sina+1/+cosa + 1+cosa/sina
=sin²a+(1+cosa)²/sina(1+cosa)
=sin²a+1+cos²a+2cosa/sina(1+cosa)
=2+2cosa/sina (1+cosa)
=2/sina
=2coseca
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