Sin -1 [cos(43pi/5)] find the value
Answers
Answered by
148
=>sin-1 [cos (8pi+3pi/5)]
=>sin-1 [cos (3pi/5)]
=> sin-1 [cos (pi/2+pi/10)]
=> sin-1 [-sin(pi/10)]
=>-sin-1 [sin(pi/10)]
=>-pi/10
=>sin-1 [cos (3pi/5)]
=> sin-1 [cos (pi/2+pi/10)]
=> sin-1 [-sin(pi/10)]
=>-sin-1 [sin(pi/10)]
=>-pi/10
abhi178:
I hope you understand
Answered by
62
To find:
Sin inverse [cos(43Π/5)] = ?
Step-by-step explanation:
By using trigonometric identities, cos trigonometric function is positive in first and fourth quadrants in coordinate axes.
As is in First quadrant, cos is positive
As is in Second quadrant, cos is negative
We know that,
On substituting the above trigonometric identity, we get,
On solving, we get,
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