Sin^-1(sinx+cosx)/√2
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NOTE that 1/root2 = cos45o = sin45o.
and sin(A+B) = sinAcosB + cosAsinB.
So sinx/root2 + cosx/root2 = sinx cos45o + cosx sin45o = sin(x+45o).
So sin-1(sinx+cosx/root2) = sin-1(sin(x+45o)) = x + 45o (or) x + pi/4
and sin(A+B) = sinAcosB + cosAsinB.
So sinx/root2 + cosx/root2 = sinx cos45o + cosx sin45o = sin(x+45o).
So sin-1(sinx+cosx/root2) = sin-1(sin(x+45o)) = x + 45o (or) x + pi/4
vasimjalegar27:
right hai na
wrong bro
what is right answer
x+45
dm bakwas answer hai
minus sin x cos x into cos x
hmmmmm
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