sinπ/12 cosπ/12 find the value??
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Answered by
4
sinπ/12cosπ/12
=2sinπ/12cosπ/12÷2
=sin2×π/12÷2
=sinπ/6÷2
=sin30°/2
=1/2×2
1/4
=2sinπ/12cosπ/12÷2
=sin2×π/12÷2
=sinπ/6÷2
=sin30°/2
=1/2×2
1/4
Answered by
16
Answer-:
Sin5π/ 12. cos π/12
Sin(π/12 - π/12). cosπ/12
cos π /12 . cos π/12
cos
π/12
cos^2 180° /12 = cosπ^2 15°
bt cos 15° = √3+1 / 2√2
Since
cos^2 15°
=> (√3+1 /2√2)^2
=> 4+2√3/8
=> 2(2+√3)/8
=> 2+√3/4
___________________________-
Sin5π/ 12. cos π/12
Sin(π/12 - π/12). cosπ/12
cos π /12 . cos π/12
cos
cos^2 180° /12 = cosπ^2 15°
bt cos 15° = √3+1 / 2√2
Since
cos^2 15°
=> (√3+1 /2√2)^2
=> 4+2√3/8
=> 2(2+√3)/8
=> 2+√3/4
___________________________-
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