Question

sin 135º - cos 240°
sin 135° + cos 240°
= a + √b, then b=​

Answer 1

Step-by-step explanation:

$sin \: {135}^{0} \: - \: cos \: {240}^{0} \\ sin \: {135}^{0} \: + \: cos \: {240}^{0} \\ = a \: + \: \sqrt{b} \\ adding \: both \: \\ 2 \: sin \: {135}^{0} \: = a \: + \: \sqrt{b} \: \\ 2 \: sin \: ({180}^{0} - {45}^{0})\: = a \: + \: \sqrt{b} \: \\ 2 \: sin \: {45}^{0}\: = a \: + \: \sqrt{b} \\ 2 \times \frac{1}{ \sqrt{2} } = \: a \: + \: \sqrt{b} \: \\ \sqrt{2} = a \: + \: \sqrt{b} \\ 0 \: + \sqrt{2} = a \: + \: \sqrt{b} \: \\ equating \: both \: sides \: \\ a = 0 \\ \sqrt{b} = \sqrt{2} \\ \implies \: b \: = \: 2$

Mark me as brainliest