Question

Sin^-1x=π/3 toh cos^-1x=π/6

Answer 1

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Answer 2

Answer:

hey

Step-by-step explanation:

Formulae used here

=> sin inverse x= theta

then

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x=sin theta

x = sin theta

in the above question theta is π/3

sin π/3 v=√3 /2

therefore

x=√3/2

put the value of x in cos inverse x

cos inverse (√3/2) = theta( required)

=theta = π/6

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