Question

Three circle of radius 3.5cm each are placed in such a way that each touches the other two. The area of the portion enclosed by the circle is? ​

Answer 1

AB = BC = AC = 7 cm

Area enclosed

= Area of equilateral △ABC-

1

2

(area of 1 circle)

=

√

3

4

×(7)2−

1

2

[

22

7

×(3.5)2]

=1.967cm2

Answer 2

First Refer Diagram!

• AB = BC = AC = 7 cm

Area Enclosed = Area of equilateral ∆ABC

= $\frac{1}{2}$ × (area of 1 circle)

= √3/4 × 7² - $\frac{1}{2}$ [ $\frac{22}{7}$ × 3.5² ]

= 1.967 cm²