Question

sin^-1x+ sin^-1y=π/2​

Answer 1

Answer:

Sin-1x + cos-1x = \Pi/2

And Given is that Sin-1x + Sin-1y = \Pi/2

Therefore , we get that...

Sin-1y = cos-1x

Sin-1y = Sin-1(\sqrt{1 - x^{2}})

Therefore

y = \sqrt{1 - x^{2}}

On Squaring both sides .

we get

x2 = 1-y2