sin^2 30+ tan^2 45- sec^2 60
please
help
Answers
Answered by
0
Answer:
-13/4
Step-by-step explanation:
sin^2 30+ tan^2 45- sec^2 60
= (sin 30)^2 + (tan 45)^2 - (sec 60)^2
= 1/4 + 1/2 -4
= 3/4 - 4
= 3-16 / 4 = -13/4
Answered by
1
Answer:
Step-by-step explanation:
sin 30° = 1/2
tan 45° = 1
sec 60° = 2
∴ sin² 30° + tan² 45° - sec² 60° = ( 1/2 )² + ( 1 )² - ( 2 )²
= 1/4 + 1 - 4
= ( 1 + 4 - 16 ) / 4
= - 11 / 4 is the answer.
Similar questions
English,
2 days ago
History,
2 days ago
Social Sciences,
4 days ago
Hindi,
4 days ago
CBSE BOARD XII,
8 months ago
English,
8 months ago