sin^(2) 45+cos^(2) 60=1
Answers
Answered by
1
hiii!!! folk.
it's too easy ....
from lhs
as you know that sin45°=1/√2 and cos60°=1/2
so,
=)sin^2 45°+cos^2 60°
=)(1/√2)+(1/2)^2
=)1/2+1/4
=)2+1/4
=)3/4........
hey your question is wrong.......
sin^245°+cos^260°=1 never ..
.
hope it help you.
@rajukumar .☺
it's too easy ....
from lhs
as you know that sin45°=1/√2 and cos60°=1/2
so,
=)sin^2 45°+cos^2 60°
=)(1/√2)+(1/2)^2
=)1/2+1/4
=)2+1/4
=)3/4........
hey your question is wrong.......
sin^245°+cos^260°=1 never ..
.
hope it help you.
@rajukumar .☺
Answered by
1
Hey there!!
Thank u for your Question ,
Here
we have ,
![{ \sin}^{2}45 + { \cos }^{2} 60 \\ \\ = > ( { \frac{1}{ \sqrt{2} }) }^{2} + { (\frac{1}{2} )}^{2} \\ \\ = > \frac{1}{2} + \frac{1}{4} \\ \\ = > \frac{3}{4} { \sin}^{2}45 + { \cos }^{2} 60 \\ \\ = > ( { \frac{1}{ \sqrt{2} }) }^{2} + { (\frac{1}{2} )}^{2} \\ \\ = > \frac{1}{2} + \frac{1}{4} \\ \\ = > \frac{3}{4}](https://tex.z-dn.net/?f=++%7B+%5Csin%7D%5E%7B2%7D45+%2B++%7B+%5Ccos+%7D%5E%7B2%7D+60+%5C%5C++%5C%5C++%3D++%26gt%3B+%28+%7B+%5Cfrac%7B1%7D%7B+%5Csqrt%7B2%7D+%7D%29+%7D%5E%7B2%7D++%2B+++%7B+%28%5Cfrac%7B1%7D%7B2%7D+%29%7D%5E%7B2%7D++%5C%5C++%5C%5C++%3D++%26gt%3B++%5Cfrac%7B1%7D%7B2%7D++%2B+%5Cfrac%7B1%7D%7B4%7D+%5C%5C++%5C%5C++%3D++%26gt%3B++%5Cfrac%7B3%7D%7B4%7D++)
Here LHS is not equal to RHS
therefore
it is wrong
Hope this helps u!!
Thank u for your Question ,
Here
we have ,
Here LHS is not equal to RHS
therefore
it is wrong
Hope this helps u!!
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