Question

sin^2*62/cos^2*28-cos^2*59/sin^2*31-4cos^2*45

Answer 1

Answer:

-2

Step-by-step explanation:

$\frac{sin^2{62}}{cos^2{28}}$ - $\frac{cos^2{59}} {sin^2{31}}$ - 4 cos²45

= $\frac{sin^2{(90-28)}}{cos^2{28}}$ - $\frac{cos^2{(90-31)}} {sin^2{31}}$ - 4 ($\frac{1}{\sqrt{2} }$)²

= $\frac{cos^2{28}}{cos^2{28}}$ - $\frac {sin^2{31}} {sin^2{31}}$ - 4 ($\frac{1}{{2} }$)

= 1 - 1 - 2

= -2

Answer 2

Answer:

sin²(90-28). cos² 59

__________ +. ________. - 4cos² 45

cos²28. sin² (90-59)

cos² 28. cos² 59. 1

________ +. _______ - 4 ( ___).²

cos² 28. cos² 59. √2

1 + 1 - 4 × 1/2

= 4.