Question

sin^2 63°+sin^2 27°/cos^2 17°+cos^73°=
?​

Answer 1

Step-by-step explanation:

=sin²(90-27)+ sin²27°/cos²(90-73)+cos²73°

=cos²27°+sin²27°/sin²73+cos²73. [cos (90 -∅)=sin∅, sin(90-∅)=cos∅]

=1/1. [as cos²A+sin²A= 1]

=1

Answer 2

$\huge\tt\purple{ \frac{ { \sin }^{2}63° + { \sin }^{2}27° }{ { \cos }^{2}17° + { \cos }^{2} 73° } }$

$\longrightarrow$$\Large\tt\purple{ \frac{ {( \sin(90°- 27°)) }^{2} + { \sin}^{2} 27°}{ {( {cos(90° - 73°)) }^{2} + { \cos }^{2} 73° } }}$

$\longrightarrow$$\huge\tt\purple{ \frac{ {( \cos27°)}^{2} + { \sin }^{2} 27°}{ {(sin73°)}^{2} + { \cos }^{2}73° } }$

$\longrightarrow$$\huge\tt\purple{\frac{ { \cos}^{2}27° + { \sin}^{2}27° }{ { \sin }^{2} 73° + { \cos}^{2}73° }}$

$\longrightarrow$$\huge\tt\purple{\frac{1}{1}}$

$\longrightarrow$$\huge\tt\purple{1}$