Question

SIn^2(90degre-thetha)+cosec^2(90-thetha)-{tan^2thetha-sin^2thetha}

Answer 1

Answer:

Step-by-step explanation:

Sin^2(90-@) + Cosec^2(90-@) -(Tan^2@ -Sin^2@)

Cos^2@ +Sec^2@ -(Tan^2@ -Sin^2@)

=Cos^2@ +Sec^2@ -Tan^2@+ Sin^2@

=Sin^2@ +Cos^2@ + Sec^2@ -Tan^2@

=1 +1

=2

$\huge{\red {Answer :::2}}}$

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