Math, asked by PRAKASHGHIMIRE, 4 months ago

sin^2 A. cos 2B - sin^2 B. cos 2A = cos^2 B - Cos^2 A​

Answers

Answered by omsingh1776
1

Answer:

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Answered by DazzleSprig
10

Step-by-step explanation:

LHS=(sinAcosB) 2 −(cosAsinB) 2

=(sinAcosB+cosAsinB)(sinAcosB−cosAsinB)

=sin(A+B)sin(A−B)

=sin 2A−sin 2 B

=RHS

Hence proved

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