solve the following pair of linear equation by the substitution method √2x+√3y=0and√3x-2√2y=0
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Answer:
2x
+
3y
=0⇒
3y
=x=−
2
3
y
3x
−
8y
=0
3
(
2
−
3y
)−
8
y=0
⇒−3y−4y=0
y=0,x=0
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