sin(π÷2)+cos(π÷4)+1÷tan(π÷4)
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solution:-
we know that:
the value of
sin π/2 = sin 90° = 1
And
cos π/4 = cos 45° = 1/ √2
And
tan π/4 = tan 45° = 1
Now
putting all the values;
we get
sin π/2 + cos π/4 + 1 / tan π/4
= 1 + 1/ √2 + 1 / 1
= 1 + 1/√2 + 1
= 2 + 1/ √2
= ( 2√2 + 1 ) / √2 Answer
# hope it helps :)
solution:-
we know that:
the value of
sin π/2 = sin 90° = 1
And
cos π/4 = cos 45° = 1/ √2
And
tan π/4 = tan 45° = 1
Now
putting all the values;
we get
sin π/2 + cos π/4 + 1 / tan π/4
= 1 + 1/ √2 + 1 / 1
= 1 + 1/√2 + 1
= 2 + 1/ √2
= ( 2√2 + 1 ) / √2 Answer
# hope it helps :)
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