sin^2 theta+3cos^2 theta=4, find the value of theta
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Hello,
sin²θ+3cos²θ=4;
from the first fundamental relationship sin²θ+cos²θ=1,
we have that:
sin²θ=1-cos²θ
so we can write it as:
1-cos²θ+3cos²θ=4;
2cos²θ=4-1;
2cos²θ=3;
cos²θ=3/2;
cosθ=√3/2;
cosθ= 30°
bye :-)
sin²θ+3cos²θ=4;
from the first fundamental relationship sin²θ+cos²θ=1,
we have that:
sin²θ=1-cos²θ
so we can write it as:
1-cos²θ+3cos²θ=4;
2cos²θ=4-1;
2cos²θ=3;
cos²θ=3/2;
cosθ=√3/2;
cosθ= 30°
bye :-)
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cos2theeta=under root 3 by under root 2
ok bro understand
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