Question

sin^2 theta cot^2 theta + cos^2theta tan ^2theta=1​

Answer 1

Answer:

Step-by-step explanation:

by using       cotФ=cosФ/sinФ    and   tanФ =sinФ/cosФ

taking the L.H.S.-

sin²Фcos²Ф/sin²Ф  +cos²Ф sin²Ф/cos²Ф

cos ²Ф +sin²Ф

=1         =R.H.S.

                      {BY sin²a+cos²a=1}

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Answer 2

Answer:

 let's solve LHS first

= sin^2 theta * cot ^2 theta + cos^2 theta * tan^2 theta

(sin^2 theta * cos^2 theta/sin^2 theta) + ( cos^2 theta * sin^2 theta/cos^2 theta) (1)

W.K.T cot^2 theta = cos^2 theta / sin^2 theta .

W.K.T tan^2 theta = sin^2 theta / cos^2 theta.

cos ^2 theta + sin^2 theta ( sin^2 theta  and cos^2 theta cuts down in equation 1)

by identity one  - cos^2 theta + sin^2 theta = 1

therefore by identity

1

LHS = RHS

Step-by-step explanation:

IT IS PROVED .HOPE YOU UNDERSTAND