Math, asked by nnarasimharao2727, 10 months ago

[sin(π/2-x)+sin(π-x)]²+ [cos(3π/2-x)+cos(2π-x)]²

Answers

Answered by snehashrivastava23

6

Answer:

2

Step-by-step explanation:

sin (π/2 - x) = cos x

sin (π - x) = (- sin x)

cos (3π/2 - x) = - sin x

cos (2π - x) = cos (- x)

Attachments:

Answered by saikrisha2006

1

the answer is 2 for the above question

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