Question

sin ^ 2018 x + cos^2018 x = ?

Answer 1

given Sin1009x whole square + cos1009 whole square.
by using basic identity it is equal to 1

Answer 2

HEY MATE HERE IS YOUR ANSWER

${ \sin(x) }^{2018} + { \cos(x) }^{2018} \\ { ({ \sin(x) }^{1009} )}^{2} + {( { \sin(x) }^{1009}) }^{2} \\ { \sin(x) }^{2} + { \cos(x) }^{2} = 1$
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