sin^24°-sin^6°=(√5-1)/8
siddhartharao77:
Is it sin^24 (or) sin^2 24.?
sin^24
Answers
Answered by
8
heya!!!
1st of all ur question is wrong ,question should be ,sin^2 24°-sin^26°=1/8(√5-1)
sin^224°-sin^26°. we have
sin(24°+sin6°)*sin(24°-6)
as we know ,sin^2A-sin^2B=sin(A+B)°sin(A-B)
above is applying this formula ..
so,sin30°*sin18°
=)1/2×(√5-1)/4
=)(√5-1)/8=Rhs. prooved .
hope it help you.
@rajukumar☺
1st of all ur question is wrong ,question should be ,sin^2 24°-sin^26°=1/8(√5-1)
sin^224°-sin^26°. we have
sin(24°+sin6°)*sin(24°-6)
as we know ,sin^2A-sin^2B=sin(A+B)°sin(A-B)
above is applying this formula ..
so,sin30°*sin18°
=)1/2×(√5-1)/4
=)(√5-1)/8=Rhs. prooved .
hope it help you.
@rajukumar☺
1/2×√5-1/4
√5-1/8=RHS
no sin60°/2=sin30°
okk
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Answered by
4
Step-by-step explanation:
We have, sin²A-sin²B=sin(A+B)sin(A-B) hence, sin²24-sin²6=sin30sin18=(1/2)(√5-1)/4=(√5-1)/8 Answer: (√5-1)/8
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