sin (240° + 0) + cos (330° + 0) = 0.
be awaré !!!!wrong answers are to be reported
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Answered by
2
LHS = sin (240°+θ) + cos(330° + θ)=sin
[270° − 30° + θ] + cos[360° − 30° + θ]=sin [270°−(30° + θ)] + cos [360° − (30° + θ)]=− cos (30° + θ) + cos (30° + θ)
[As, sin(270°−θ) = − cos θ, cos (360° − θ) = cos θ]=0=RHS
HOPE IT IS HELPFUL
Answered by
6
Please refer the attachment.........
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