Question

Sin(270°-theeta)sin(90°-theeta)-cos(270°-theeta) cos(90°+theeta)+1=0

Answer 1

Answer:

this would be ur question:-

Sin ( 180 + theta ) cos ( 90 + theta ) tan ( 270 + theta )cot ( 360 + theta) / sin ( 360 - theta ) cos ( 360 + theta ) cosec ( -theta ) sin ( 270 + theta )

solutions:-

sin(180°+θ)cos(90°°+θ)tan(270°+θ)cot(360°+θ)/sin(360°-θ)cos(360°+θ)cosec(-θ)sin(270°+θ)

=-sinθ.sinθ.(-cotθ).cotθ/(-sinθ).cosθ.(-cosecθ)(-cosθ)

=sin²θ(-cot²θ)/sinθ.cosecθ.(-cos²θ)

={(sin²θ)(cos²θ/sin²θ)}/(sinθ)(1/sinθ)(cos²θ)

=(cos²θ)/(cos²θ)

=1