Sin 2A=√2sin A then find A
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Here is your answer :-
Sin2A = √2 sinA
2sinAcosA = √2sinA ( sin2A = 2sinAcosA)
2cosA = √2
cosA = √2/2
cosA = 1/√2
cosA = cos 45°
A = 45°
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Here is your answer :-
Sin2A = √2 sinA
2sinAcosA = √2sinA ( sin2A = 2sinAcosA)
2cosA = √2
cosA = √2/2
cosA = 1/√2
cosA = cos 45°
A = 45°
if u like my answer then pls mark as brainliest
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